The equation of the plane, parallel to the plane 3x + 4y - 12z = 3 and passes through (1, 1, -1), is : Option 1: 3x + 4y - 12z = 0 Option 2: 3x + 4y + 12z = 3 Option 3: 3x + 4y - 12z = 19 Option 4: 3x + 4y - 12z = 22

The answer is '3x + 4y - 12z = 19'. View full solution:

CUET Mathematics - The equation of the plane, parallel to the plane 3x + 4y - 12z = 3 and passes through (1, 1, -1), is : | PYQs + Solutions

CUET Mathematics 2022 17 Aug Shift 2

Geometry

Easy

$3x + 4y - 12z = 0$

$3x + 4y + 12z = 3$

$3x + 4y - 12z = 19$

$3x + 4y - 12z = 22$

✅ Correct Option: 3

Related questions:

22 May Shift 2

Match List-I with List-II

List-I	List-II
Equation of line	Information
(A) $\vec{r} = (3\hat{i} - 2\hat{j} + \hat{k}) + \lambda(\hat{j} - 2\hat{k})$	(I) Direction ratios are 2, 4, -1
(B) $\frac{2-x}{1} = \frac{2y+1}{4}$ , $z = 2$	(II) Perpendicular to $2\hat{i} - \hat{j} + \hat{k}$
(C) $\frac{x}{1} = \frac{y-3}{2} = \frac{3-4z}{2}$	(III) Passing through the point $(3, -2, 1)$
(D) $\vec{r} = (3\hat{i} + 2\hat{j} + \hat{k}) + \lambda(2\hat{i} + \hat{j} - 3\hat{k})$	(IV) Direction ratios are -1, 2, 0

Choose the correct answer from the options given below:

6 Aug Shift 2

The equation of plane passing through the point of (3, 2, 0) and containing the line $\frac{x-2}{2} = \frac{y+3}{4} = \frac{z-1}{1}$ is

15 June Shift 2

If the straight lines $x = 1 + s$ , $y = -3 - \lambda s$ , $z = 1 + \lambda s$ and $x = \frac{t}{2}$ , $y = 1 + t$ , $z = 2 - t$ with parameters $s$ and $t$ respectively, are coplanar, then $\lambda$ is equal to :

CUET Mathematics 2022 17 Aug Shift 2 PYQs

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