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If A=[200−123335]A=\begin{bmatrix}2 & 0 & 0 \\ -1 & 2 & 3 \\ 3 & 3 & 5\end{bmatrix}, then A(adj A)A(\text{adj } A) is equal to :

Solution

✅ Correct Option: 3

A(adj A)=∣A∣IA(\text{adj } A) = |A| I. Computing ∣A∣|A|: expanding along first row, ∣A∣=2(10−9)=2|A| = 2(10-9) = 2. So A(adj A)=2IA(\text{adj } A) = 2I.

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