The area (in square units) bounded by the curve $y^2 = 4x$ and the line $x=1$ is :

Area of the region bounded by the curve $y^2 = 4x$, $y$-axis and the line $y = 3$ is equal to

Area bounded by the curves

$y=\begin{cases}x+2, & x\ge-1\\-x, & x<-1\end{cases}$, $x=-2, x=3$ and $y=0$ is:

The area of region $R = \{(x,y): x^2 + y^2 \le 16, y \le \sqrt{3}x, x \ge 0, y \ge 0\}$ is: (in Sq. units)

The nearest integral value of the shaded area shown below is:

The area bounded by $x = \sqrt{9 - y^2}$, $x - y + 3 = 0$ and x-axis is :

The area (in sq. units) of the region in the first quadrant enclosed between the line $x + y = 2$, parabola $y^2 = x$ and the x-axis, is