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If A=[2x0xx]A = \begin{bmatrix} 2x & 0 \\ x & x \end{bmatrix} and A−1=[10−12]A^{-1} = \begin{bmatrix} 1 & 0 \\ -1 & 2 \end{bmatrix}, then the value of xx is

Solution

✅ Correct Option: 4

Compute A⋅A−1=IA \cdot A^{-1} = I.

[2x0xx][10−12]=[2x002x]\begin{bmatrix} 2x & 0 \\ x & x \end{bmatrix} \begin{bmatrix} 1 & 0 \\ -1 & 2 \end{bmatrix} = \begin{bmatrix} 2x & 0 \\ 0 & 2x \end{bmatrix}.

This equals II when 2x=12x = 1, so x=12x = \frac{1}{2}.

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