Q1:

IPMAT Indore 2026

Progression & Series

Hard

Gita starts from point A and walks 1000 m east. She then walks 800 m north, followed by 640 m west and 512 m south, reaching point B. After this, she continues moving in the same cyclic order: east, north, west, south, with each successive movement 20% shorter than the previous one. After infinitely many such moves, approximately how far in meters will Gita be from her starting point A?

Answer options
Option 4
Correct Answer
Explanation for IPMAT Indore 2026 MCQ question 1

Q2:

IPMAT Indore 2026

Progression & Series

Medium

Let SS denote an arithmetic progression whose first term is either 132 or 158, and the common difference is an even integer less than 10. If the nthn^{\text{th}} term of SS is 174, then the number of possible distinct values of nn is ___

Q3:

IPMAT Indore 2026

Progression & Series

Medium

A certain number of people contributed to a charity. The first person contributed one rupee. The rule for contribution was that the next person would contribute double the amount already raised. If the total money raised for the charity was 2187 rupees, then the number of people who contributed to the charity is

Answer options
Option 3
Correct Answer
Explanation for IPMAT Indore 2026 MCQ question 3

Q4:

IPMAT Indore 2025

Progression & Series

Medium

Given that 1+122+132+142+...=π261 + \frac{1}{2^2} + \frac{1}{3^2} + \frac{1}{4^2} + ... = \frac{\pi^2}{6}, the value of 1+132+152+172+...1 + \frac{1}{3^2} + \frac{1}{5^2} + \frac{1}{7^2} + ... is

Answer options
Option 4
Correct Answer
Explanation for IPMAT Indore 2025 MCQ question 4

Q5:

IPMAT Indore 2025

Progression & Series

Medium

If the sum of the first 2121 terms of the sequence: lnab,lnabb,lnab2,lnab2b,\ln \frac{a}{b}, \ln \frac{a}{b \sqrt{b}}, \ln \frac{a}{b^{2}}, \ln \frac{a}{b^{2} \sqrt{b}}, \ldots is lnambn\ln \frac{a^{m}}{b^{n}}, then the value of m+nm+n is \qquad

Q6:

IPMAT Indore 2025

Progression & Series

Medium

The sum of the first 5 terms of a geometric progression is the same as the sum of the first 7 terms of the same progression. If the sum of the first 9 terms is 24, then the 4th term of the progression is

Answer options
Option 2
Correct Answer
Explanation for IPMAT Indore 2025 MCQ question 6

Q7:

IPMAT Indore 2025

Progression & Series

Medium

Let S1={100,105,110,115,...}S_1 = \{100, 105, 110, 115, ... \} and S2={100,95,90,85,...}S_2 = \{100, 95, 90, 85, ... \} be two series in arithmetic progression. If aka_k and bkb_k are the kk-th terms of S1S_1 and S2S_2, respectively, then k=120akbk\sum_{k=1}^{20} a_k b_k equals __________.

Answer options
Option 2
Correct Answer
Explanation for IPMAT Indore 2025 MCQ question 7

Q8:

IPMAT Indore 2024

Progression & Series

Hard

The terms of a geometric progression are real and positive. If the pp-th term of the progression is qq and the qq-th term is pp, then the logarithm of the first term is

Answer options
Option 2
Correct Answer
Explanation for IPMAT Indore 2024 MCQ question 8

Q9:

IPMAT Indore 2024

Progression & Series

Medium

The sum of a given infinite geometric progression is 80 and the sum of its first two terms is 35. Then the value of nn for which the sum of its first nn terms is closest to 100, is

Answer options
Option 2
Correct Answer
Explanation for IPMAT Indore 2024 MCQ question 9

Q10:

IPMAT Indore 2023

Progression & Series

Hard

If f(n)=1+2+3++(n+1)f(n)= 1 + 2 + 3 +\cdots+(n+1) and g(n)=k=1k=n1f(k)g(n)= \sum_{k=1}^{k=n} \dfrac{1}{f(k)}, then the least value of nn for which g(n)g(n) exceeds the value 99100\dfrac{99}{100} is:

Q11:

IPMAT Indore 2023

Progression & Series

Medium

Let a1,a2,a3a_{1}, a_{2}, a_{3} be three distinct real numbers in geometric progression. If the equations a1x2+2a2x+a3=0a_{1} x ^ 2 + 2a_{2}x + a_{3} = 0 and b1x2+2b2x+b3=0b_{1} x ^ 2 + 2b_{2}x + b_{3} = 0 have a common root, then which of the following is necessarily true?

Answer options
Option 4
Correct Answer
Explanation for IPMAT Indore 2023 MCQ question 11

Q12:

IPMAT Indore 2023

Progression & Series

Hard

A person standing at the centre of an open ground first walks 32 meters towards the east, takes a right turn and walks 16 meters, takes another right turn and walks 8 meters, and so on. How far will the person be from the original starting point after an infinite number of such walks in this pattern?

Answer options
Option 4
Correct Answer
Explanation for IPMAT Indore 2023 MCQ question 12

Q13:

IPMAT Indore 2022

Progression & Series

Medium

A new sequence is obtained from the sequence of positive integers (1,2,3,)(1,2,3, \ldots) by deleting all the perfect squares. Then the 2022nd 2022^{\text {nd }} term of the new sequence is ________.

Q14:

IPMAT Indore 2022

Progression & Series

Medium

The 3rd ,14th 3^{\text {rd }}, 14^{\text {th }} and 69th 69^{\text {th }} terms of an arithmetic progression form three distinct and consecutive terms of a geometric progression. If the next term of the geometric progression is the nth n^{\text {th }} term of the arithmetic progression, then nn equals ________.

Q15:

IPMAT Indore 2022

Progression & Series

Medium

The sum of the first 15 terms in an arithmetic progression is 200, while the sum of the next 15 terms is 350. Then the common difference is

Answer options
Option 2
Correct Answer
Explanation for IPMAT Indore 2022 MCQ question 15

Q16:

IPMAT Indore 2022

Progression & Series

Medium

The numbers 16,2x+322x116,22x1+16-16,2^{x+3}-2^{2 x-1}-16,2^{2 x-1}+16 are in an arithmetic progression. Then xx equals ________.

Q17:

IPMAT Indore 2021

Progression & Series

Medium

The sum up to 1010 terms of the series 13+57+911+...1 \cdot 3 + 5 \cdot 7 + 9 \cdot 11 + ... is

Q18:

IPMAT Indore 2021

Progression & Series

Medium

Let SnS_n be sum of the first nn terms of an A.P. If S5=S9S_5 = S_9, what is the ratio of a3:a5a_3 : a_5

Answer options
Option 1
Correct Answer
Explanation for IPMAT Indore 2021 MCQ question 18

Q19:

IPMAT Indore 2021

Progression & Series

Medium

It is given that the sequence {xnx_n} satisfies x1=0,xn+1=xn+1+2(1+xn)x_1 = 0, x_{n+1} = x_n + 1 + 2√(1+x_n) for n=1,2,...n = 1,2,... Then x31x_{31} is _______

Q20:

IPMAT Indore 2020

Progression & Series

Hard

If 112+122+132+\frac{1}{1^2} + \frac{1}{2^2} + \frac{1}{3^2} + \ldots up to =π26\infty = \frac{\pi^2}{6}, then the value of 112+132+152+\frac{1}{1^2} + \frac{1}{3^2} + \frac{1}{5^2} + \ldots up to \infty is

Answer options
Option 1
Correct Answer
Explanation for IPMAT Indore 2020 MCQ question 20

Q21:

IPMAT Indore 2019

Progression & Series

Medium

Assume that all positive integers are written down consecutively from left to right as in 1234567891011...... The 6389th digit in this sequence is

Q22:

IPMAT Indore 2019

Progression & Series

Hard

Let α,β\alpha, \beta be the roots of x2x+p=0x^2 - x + p = 0 and γ,δ\gamma, \delta be the roots of x24x+q=0x^2 - 4x + q = 0 where p and q are integers. If α,β,γ,δ\alpha, \beta, \gamma, \delta are in geometric progression then p+qp + q is

Answer options
Option 1
Correct Answer
Explanation for IPMAT Indore 2019 MCQ question 22

Q23:

IPMAT Indore 2019

Progression & Series

Hard

If (1+x2x2)6=A0+r=112Arxr(1 + x - 2x^2)^6 = A_0 + \sum_{r=1}^{12} A_r x^r, then the value of A2+A4+A6++A12A_2 + A_4 + A_6 + \cdots + A_{12} is

Answer options
Option 1
Correct Answer
Explanation for IPMAT Indore 2019 MCQ question 23

Q24:

IPMAT Indore 2019

Progression & Series

Easy

The number of terms common to both the arithmetic progressions 2,5,8,11,...,1792, 5, 8, 11, ..., 179 and 3,5,7,9,...,1013, 5, 7, 9, ..., 101 is

Answer options
Option 1
Correct Answer
Explanation for IPMAT Indore 2019 MCQ question 24

Q25:

IPMAT Indore 2019

Progression & Series

Medium

There are numbers a1,a2,a3,,ana_1, a_2, a_3, \ldots, a_n each of them being +1+1 or 1-1. If it is known that a1a2+a2a3+a3a4+an1an+ana1=0a_1 a_2 + a_2 a_3 + a_3 a_4 + \ldots a_{n-1} a_n + a_n a_1 = 0 then

Answer options
Option 3
Correct Answer
Explanation for IPMAT Indore 2019 MCQ question 25