Assertion [A]: Sum of the first hundred even natural numbers divisible by 5 is 45050.
Reason (R): Sum of the first n-terms of an Arithmetic Progression is given by where a=first term, l=last term.
Choose the correct answer from the options given below.
Assertion [A]: Sum of the first hundred even natural numbers divisible by 5 is 45050.
Reason (R): Sum of the first n-terms of an Arithmetic Progression is given by where a=first term, l=last term.
Choose the correct answer from the options given below.
Solution
✅ Correct Option: 4
- First, let's verify if [A] is true:
- First hundred even numbers divisible by 5: 10, 20, 30,..., 1000
- This forms an AP with:
- First term
- Common difference
- Number of terms
- Last term
- This forms an AP with:
- Using formula given in [R]:
=
=
=
- Therefore, [A] is false as it states sum is 45050.
- Let's verify if [R] is true:
- The formula given is indeed correct for arithmetic progression
- This is a standard formula for sum of AP
- Therefore [R] is true
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