CUET Mathematics: CalculusDifferential Equations. Free, no login required.

Q1:

2025: 15 May Shift 1

Differential Equations

Medium

Applied

Let y(x)=a(x+1)log⁡(x+1)+bx+5y(x) = a(x + 1) \log(x + 1) + bx + 5 be the solution of the differential equation edydx=x+1;y(0)=5^\frac{dy}{dx} = x + 1_{;}y(0) = 5, then the value of (a+b)(a + b) is:

Answer options
Option 1
Correct Answer
Explanation for 2025: 15 May Shift 1 MAT question 1

Q2:

2025: 14 May Shift 2

Differential Equations

Medium

Common

Match List-I with List-II

List-IList-II
Differential EquationsOrder and degree
(A) dydx+ey=0\frac{dy}{dx} + e^y = 0(I) order 2, degree not defined
(B) d2ydx2=[1+(dydx)2]3/2\frac{d^2y}{dx^2} = \left[1 + \left(\frac{dy}{dx}\right)^2\right]^{3/2}(II) order 2, degree 1
(C) (d2ydx2)2+e(dydx)=0\left(\frac{d^2y}{dx^2}\right)^2 + e^{(\frac{dy}{dx})} = 0(III) order 1, degree 1
(D) d2ydx2+xdydx−2y=logx;x>0\frac{d^2y}{dx^2} + x\frac{dy}{dx} - 2y = logx; x > 0(IV) order 2, degree 2

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Answer options
Option 1
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 2

Q3:

2025: 14 May Shift 2

Differential Equations

Medium

Common

Particular solution of the differential equation x(1+y2)dx−y(1+x2)dy=0x(1 + y^2)dx - y(1 + x^2)dy = 0, given y=0y = 0 when x=1x = 1, is

Answer options
Option 1
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 3

Q4:

2025: 14 May Shift 2

Differential Equations

Medium

Core

General solution of the differential equation dydx=ex22+xy\frac{dy}{dx} = e^{\frac{x^2}{2}} + xy is

Answer options
Option 3
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 4

Q5:

2025: 14 May Shift 2

Differential Equations

Medium

Core

For the differential equation (x+y)dy+(x−y)dx=0(x + y)dy + (x - y)dx = 0, which of the following is/are correct?

(A) Differential equation is homogeneous

(B) Order of differential equation is 1

(C) Integrating factor of differential equation is exe^x

(D) Degree of the equation is not defined

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Answer options
Option 4
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 5

Q6:

2025: 14 May Shift 2

Differential Equations

Medium

Applied

The general solution of the differential equation dydx=ex−y+x2e−y\frac{dy}{dx} = e^{x-y} + x^2e^{-y} is equal to:

Answer options
Option 1
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 6

Q7:

2025: 14 May Shift 1

Differential Equations

Medium

Common

The solution of the differential equation loge(dydx)=3x+4ylog_e\left(\frac{dy}{dx}\right) = 3x + 4y is given by

Answer options
Option 1
Correct Answer
Explanation for 2025: 14 May Shift 1 MAT question 7

Q8:

2025: 14 May Shift 1

Differential Equations

Medium

Common

Which of the following are linear first order differential equations?

(A) dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x)

(B) dxdy+P(y)x=Q(y)\frac{dx}{dy} + P(y)x = Q(y)

(C) (x−y)dydx=x+2y(x - y)\frac{dy}{dx} = x + 2y

(D) (1+x2)dydx+2xy=2(1 + x^2)\frac{dy}{dx} + 2xy = 2

Choose the correct answer from the options given below:

Answer options
Option 1
Correct Answer
Explanation for 2025: 14 May Shift 1 MAT question 8

Q9:

2025: 14 May Shift 1

Differential Equations

Hard

Core

Consider the differential equation, xdydx=y(log⁡ey−log⁡ex+1)x\frac{dy}{dx} = y(\log_e y - \log_e x + 1), then which of the following are true?

(A) It is a linear differential equation

(B) It is a homogenous differential equation

(C) Its general solution is log⁡e(yx)=Cx\log_e\left(\frac{y}{x}\right) = Cx, where C is constant of integration

(D) Its general solution is log⁡e(xy)=Cy\log_e\left(\frac{x}{y}\right) = Cy, where C is constant of integration

(E) If y(1)=1y(1) = 1, then its particular solution is y=xy = x

Choose the correct answer from the options given below:

Answer options
Option 4
Correct Answer
Explanation for 2025: 14 May Shift 1 MAT question 9

Q10:

2025: 14 May Shift 1

Differential Equations

Medium

Core

The integrating factor of the differential equation (xlogex)dydx+y=2logex(x log_e x)\frac{dy}{dx} + y = 2log_e x is

Answer options

Q11:

2025: 14 May Shift 1

Differential Equations

Hard

Applied

Let eαy+eβy+γx2+δlog⁡∣x∣+C=0e^{\alpha y} + e^{\beta y} + \gamma x^2 + \delta \log|x| + C = 0, where C∈RC \in \mathbb{R} be a particular solution of the differential equation x(e2y−1)dy+(x2−1)eydx=0x(e^{2y} - 1)dy + (x^2 - 1)e^ydx = 0 and passes through the point (1,1)(1, 1). The value of (α+β+γ+δ−C)(\alpha + \beta + \gamma + \delta - C) is

Answer options

Q12:

2025: 13 May Shift 2

Differential Equations

Medium

Common

The general solution of the differential equation

dydx=xy+x+y+1\frac{dy}{dx} = xy + x + y + 1 is

Answer options

Q13:

2025: 13 May Shift 2

Differential Equations

Hard

Common

Match List-I with List-II

List-IList-II
Differential equationDegree
(A) d2ydx2+dydx−y=0\frac{d^2y}{dx^2} + \sqrt{\frac{dy}{dx}} - y = 0(I) 6
(B) d3ydx3−d2ydx212=0\sqrt{\frac{d^3y}{dx^3}} - \sqrt[12]{\frac{d^2y}{dx^2}} = 0(II) Not defined
(C) (d2ydx2)2+dydx+edxdx=x2\left(\frac{d^2y}{dx^2}\right)^2 + \frac{dy}{dx} + e^{\frac{dx}{dx}} = x^2(III) 3
(D) dydx3−d2ydx2=ex\sqrt[3]{\frac{dy}{dx}} - \frac{d^2y}{dx^2} = e^x(IV) 2

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Q14:

2025: 13 May Shift 2

Differential Equations

Medium

Core

The integrating factor of the differential equation, x2dydx+xy=logexx^2 \frac{dy}{dx} + xy = log_e x is equal to

Answer options

Q15:

2025: 13 May Shift 2

Differential Equations

Medium

Core

The general solution of differential equation dydx=ex+y\frac{dy}{dx} = e^{x+y} is

Answer options

Q16:

2025: 13 May Shift 2

Differential Equations

Medium

Applied

The general solution of the differential equation exdy+(yex+2x)dx=0e^x dy + (y e^x + 2x)dx = 0 is

Answer options

Q17:

2025: 13 May Shift 1

Differential Equations

Easy

Common

Let the degree and order of the differential equation 2x3dydx−5(d2ydx2)2=6(dydx)32x^3\frac{dy}{dx}-5\left(\frac{d^2y}{dx^2}\right)^2=6\left(\frac{dy}{dx}\right)^3 be mm and nn respectively. Then

(A) m = 2

(B) n = 3

(C) m = 3

(D) mn = 4

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Q18:

2025: 13 May Shift 1

Differential Equations

Medium

Common

The general solution of the differential equation log⁡e(dydx)=ax+by\log_e\left(\frac{dy}{dx}\right) = ax + by is

Answer options

Q19:

2025: 13 May Shift 1

Differential Equations

Medium

Core

The general solution of the differential equation ydx−(x+2y2)dy=0ydx - (x + 2y^2)dy = 0

Answer options

Q20:

2025: 13 May Shift 1

Differential Equations

Medium

Core

Match List-I with List-II

List-IList-II
Differential equationIntegrating factor
(A) xdydx−y=2x2x\frac{dy}{dx} - y = 2x^2(I) e−ye^{-y}
(B) dydx+yx=2x\frac{dy}{dx} + \frac{y}{x} = 2x(II) 1x\frac{1}{x}
(C) xdydx+2y=x2logxx\frac{dy}{dx} + 2y = x^2logx(III) xx
(D) dxdy−x=y\frac{dx}{dy} - x = y(IV) x2x^2

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Q21:

2025: 13 May Shift 1

Differential Equations

Hard

Applied

The particular solution of the differential equation ex1−y2dx+yxdy=0e^x\sqrt{1-y^2}dx + \frac{y}{x}dy = 0, given that y=1y = 1, when x=0x = 0 is:

Answer options

Q22:

2024: 16 May Shift 1

Differential Equations

Easy

Common

The degree of the differential equation (1−(dydx)2)32=kd2ydx2\left(1-\left(\frac{d y}{d x}\right)^{2}\right)^{\frac{3}{2}}=k \frac{d^{2} y}{d x^{2}} is :

Answer options

Q23:

2024: 16 May Shift 1

Differential Equations

Medium

Core

Choose the correct answer from the options given below:

List-IList-II
(A) Integrating factor of x dy−(y+2x2) dx=0x \, dy - (y + 2x^2) \, dx = 0(I) 1x\frac{1}{x}
(B) Integrating factor of (2x2−3y) dx=x dy(2x^2 - 3y) \, dx = x \, dy(II) xx
(C) Integrating factor of (2y+3x2) dx+x dy=0(2y + 3x^2) \, dx + x \, dy = 0(III) x2x^2
(D) Integrating factor of 2x dy+(3x3+2y) dx=02x \, dy + (3x^3 + 2y) \, dx = 0(IV) x3x^3
Answer options

Q24:

2024: 16 May Shift 1

Differential Equations

Medium

Core

If sin⁡y=xsin⁡(a+y)\sin y=x \sin (a+y), then dydx\frac{d y}{d x} is :

Answer options

Q25:

2024: 16 May Shift 1

Differential Equations

Medium

Core

For the differential equation (xlog⁡ex)dy=(log⁡ex−y)dx\left(x \log _{e} x\right) d y=\left(\log _{e} x-y\right) d x

(A) Degree of the given differential equation is 11.

(B) It is a homogeneous differential equation.

(C) Solution is 2ylog⁡ex+A=(log⁡ex)22y \log _{\mathrm{e}} \mathrm{x}+A=\left(\log _{\mathrm{e}} \mathrm{x}\right)^{2}, where AA is an arbitrary constant

(D) Solution is 2ylog⁡ex+A=log⁡e(log⁡ex)2 y \log _{e} x+A=\log _{e}\left(\log _{e} x\right), where AA is an arbitrary constant

Choose the correct answer from the options given below :

Answer options

Q26:

2023: 23 May Shift 3

Differential Equations

Medium

Common

In the context of differential equation

Match List I with List II

LIST ILIST II
A. dydx=1+y21+x2\frac{dy}{dx} = \frac{1+y^2}{1+x^2}I. Not a differential equation
B. x2dydx=x2−2y2+xyx^2 \frac{dy}{dx} = x^2 - 2y^2 + xyII. Linear first order
C. sin⁡x+y=cos⁡(x+y)\sin x + y = \cos(x+y)III. Variable separable
D. (x+y)dydx=1(x+y)\frac{dy}{dx} = 1IV. Homogenous

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Q27:

2023: 23 May Shift 3

Differential Equations

Hard

Common

Which of the following differential equation represents the family of circles touching the x-axis at the origin ?

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Q28:

2023: 23 May Shift 3

Differential Equations

Medium

Core

The solution of y′−y′′=2xy' - y'' = 2x is:

A. y=x2+2x+2y = x^2 + 2x + 2

B. y=x2+2x+1y = x^2 + 2x + 1

C. y=x+2y = x + 2

D. y=x2−2x+1y = x^2 - 2x + 1

Choose the correct answer from the options given below:

Answer options

Q29:

2023: 23 May Shift 3

Differential Equations

Easy

Core

The general solution of dydx=1+x2+y2+x2y2\frac{dy}{dx} = 1 + x^2 + y^2 + x^2y^2 is:

(given that CC is the constant of integration)

Answer options

Q30:

2023: 22 May Shift 3

Differential Equations

Medium

Common

The differential equation of the family of curves y=asin⁡(bx+c)y = a \sin(bx + c), a and c are parameters, is :

Answer options