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Mohan wishes to purchase a house for ₹10,000,000 with a down payment of ₹20,00,00.00. If he pays the balance amount in 25 years by equal monthly instalment at 9% compounded monthly, then the total interest paid by Mohan is:

[Use (1.0075)300=9.4084(1.0075)^{300} = 9.4084]

Solution

✅ Correct Option: 2

Loan =1,00,00,000−20,00,000=80,00,000=1,00,00,000-20,00,000=80,00,000, with i=0.0075i=0.0075 and n=300n=300.

EMI=Pi1−(1+i)−n=600001−19.4084≈67,136EMI=\frac{Pi}{1-(1+i)^{-n}}=\frac{60000}{1-\frac{1}{9.4084}}\approx 67,136.

Total paid ≈67,136×300≈2,01,40,800\approx 67,136\times300\approx 2,01,40,800, so interest ≈1,21,40,716\approx 1,21,40,716.

Note: The down payment is printed as ₹20,00,00.00; we have read it as ₹20,00,000, which is what makes the given data consistent.

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