Skip to main contentSkip to solution

If y2=ax+b,a,b∈Ry^2 = ax + b, a,b \in \mathbb{R} where R\mathbb{R} is the set of real numbers, then yd2ydx2+(dydx)2y\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 is equal to:

Solution

✅ Correct Option: 1

Differentiating y2=ax+by^2=ax+b gives 2ydydx=a2y\frac{dy}{dx}=a.

Since aa is constant, differentiate again: 2[yd2ydx2+(dydx)2]=02\left[y\frac{d^2y}{dx^2}+\left(\frac{dy}{dx}\right)^2\right]=0.

Hence the required expression equals 00.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question