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If A=[k22k]A=\begin{bmatrix}k & 2\\2 & k\end{bmatrix} such that ∣A3∣=125\lvert A^3 \rvert = 125 then which of the following statements are TRUE?

(A) ∣k.adj(3A)∣=405\lvert k.adj(3A) \rvert = 405

(B) ∣k.adj(3A)∣=2025\lvert k.adj(3A) \rvert = 2025

(C) ∣adj(3A)∣=95\lvert adj(3A) \rvert = 95

(D) ∣adj(3A)∣=45\lvert adj(3A) \rvert = 45

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

∣A∣=k2−4|A|=k^2-4 and ∣A3∣=∣A∣3=125|A^3|=|A|^3=125 gives ∣A∣=5|A|=5, so k2=9k^2=9 and k2−4=5k^2-4=5.

For order 22: ∣3A∣=32∣A∣=45|3A|=3^2|A|=45 and ∣adj(3A)∣=∣3A∣2−1=45|adj(3A)|=|3A|^{2-1}=45, so (D) is true.

Also ∣k adj(3A)∣=k2×45=9×45=405|k\,adj(3A)|=k^2\times45=9\times45=405, so (A) is true.

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