Statistics & Applications

Financial Math

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A person invested ₹2,00,000 in a mutual fund in year 2012. The value of the mutual fund increased to ₹3,00,000 in year 2017. The percentage of compound annual growth rate on the investment is:

(Given: $(1.5)^{1/5} = 1.084$ )

9.2%

8.4%

7.6%

8.8%

✅ Correct Option: 2

$CAGR=\left(\frac{\text{final}}{\text{initial}}\right)^{1/n}-1$ with $n=5$ years.

$=\left(\frac{300000}{200000}\right)^{1/5}-1=(1.5)^{1/5}-1=1.084-1=0.084$ .

Hence the growth rate is $8.4\%$ .

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A person invested ₹2,00,000 in a mutual fund in year 2012. The value of the mutual fund increased to ₹3,00,000 in year 2017. The percentage of compound annual growth rate on the investment is: (Given: (1.5)1/5=1.084(1.5)^{1/5} = 1.084(1.5)1/5=1.084)

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CUET Mathematics Past Year Questions (Topic-Wise)

A person invested ₹2,00,000 in a mutual fund in year 2012. The value of the mutual fund increased to ₹3,00,000 in year 2017. The percentage of compound annual growth rate on the investment is:

(Given: $(1.5)^{1/5} = 1.084$ )