CUET Mathematics - Match List-I with List-II | List-I: Linear differential equation | List-II: Integrating factor | |---|---| | (A) xdy/dx-y=2x^3 | (I) e^-x | | (B) 2xdy/dx+y=3x^2 | (II) e^x | | (C) dy/dx+y= x- x | (III) x^1/2 | | (D) dy/dx-y=e^x | (IV) 1/x | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 2

Calculus

Medium

core

(A) - (II), (B) - (III), (C) - (IV), (D) - (I)

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

(A) - (IV), (B) - (II), (C) - (III), (D) - (I)

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

✅ Correct Option: 4

Related questions:

16 July Shift 2

Integrating factor of the differential equation $\frac{dy}{dx} - \frac{1}{x} y = 1$ is:

14 May Shift 2

Match List-I with List-II

List-I	List-II
Differential Equations	Order and degree
(A) $\frac{dy}{dx} + e^y = 0$	(I) order 2, degree not defined
(B) $\frac{d^2y}{dx^2} = \left[1 + \left(\frac{dy}{dx}\right)^2\right]^{3/2}$	(II) order 2, degree 1
(C) $\left(\frac{d^2y}{dx^2}\right)^2 + e^{(\frac{dy}{dx})} = 0$	(III) order 1, degree 1
(D) $\frac{d^2y}{dx^2} + x\frac{dy}{dx} - 2y = logx; x > 0$	(IV) order 2, degree 2

Choose the correct answer from the options given below:

22nd May Shift 2

The product of the order and degree of the differential equation $\left(\frac{d^3y}{dx^3}\right)^2 - 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^4$ is

CUET Mathematics 2026 22nd May Shift 2 PYQs

Keyboard Shortcuts