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If A (a, a − b), B (a + b, − b) and C (b, a) are three collinear points, where a, b, c, ∈R\in \mathbb{R}, then :

Solution

✅ Correct Option: 2

Three points are collinear when the determinant formed by rows (a, a−b, 1)(a,\,a-b,\,1), (a+b, −b, 1)(a+b,\,-b,\,1) and (b, a, 1)(b,\,a,\,1) is zero.

Expanding: a(−b−a)−(a−b)(a)+(a2+ab+b2)=−a2+ab+b2=0a(-b-a)-(a-b)(a)+(a^2+ab+b^2)=-a^2+ab+b^2=0.

Rearranging gives a2−b2=aba^2-b^2=ab.

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