Three pipes A, B & C fill a tank in 3 hours working simultaneously. The pipe C is twice as faster as B and B is twice as fast as A. The time taken by pipe A alone to fill the tank is:
Three pipes A, B & C fill a tank in 3 hours working simultaneously. The pipe C is twice as faster as B and B is twice as fast as A. The time taken by pipe A alone to fill the tank is:
Solution
Three pipes A, B, and C fill a tank in 3 hours working simultaneously. Pipe C is twice as fast as B, and B is twice as fast as A.
Let pipe A take hours to fill the tank alone.
Since B is twice as fast as A, pipe B takes hours alone.
Since C is twice as fast as B, pipe C takes hours alone.
If a pipe fills a tank in hours, it fills of the tank in 1 hour.
In 1 hour:
Pipe A fills of the tank
Pipe B fills of the tank
Pipe C fills of the tank
All three pipes together in 1 hour:
of the tank
All three pipes fill the tank in 3 hours, so the work done in 1 hour multiplied by 3 equals 1 complete tank:
Therefore, pipe A alone takes 21 hours to fill the tank.