If A (3, 2), B (1, -1) and C (2, 1) are three vertices of a parallelograms ABCD, then its area (in sq.units) is equal to
If A (3, 2), B (1, -1) and C (2, 1) are three vertices of a parallelograms ABCD, then its area (in sq.units) is equal to
Solution
Given three vertices of parallelogram ABCD:
A(3, 2)
B(1, -1)
C(2, 1)
The area of a parallelogram can be found using any three consecutive vertices by calculating the cross product of two adjacent sides.
Vector AB represents the side from A to B:
Vector AB = B - A
Vector AB = (1 - 3, -1 - 2)
Vector AB = (-2, -3)
Vector AC represents the side from A to C:
Vector AC = C - A
Vector AC = (2 - 3, 1 - 2)
Vector AC = (-1, -1)
For a parallelogram with adjacent sides represented by vectors (x₁, y₁) and (x₂, y₂):
Area =
Substituting AB = (-2, -3) and AC = (-1, -1):
Area =
Area =
Area =
Area =
Therefore, the area of parallelogram ABCD is 1 square unit.
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