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If A=[0x2−6−3−x0−8x2−2x80]A = \begin{bmatrix}0 & x^2-6 & -3\\-x & 0 & -8\\x^2-2x & 8 & 0\end{bmatrix} is a skew symmetric matrix, then the value(s) of x is/ are -

(A) 3

(B) -3

(C) -2

(D) -1

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

A skew-symmetric matrix satisfies AT=−AA^T = -A, which means aij=−ajia_{ij} = -a_{ji} for all elements. The diagonal elements are always zero.

Given: A=[0x2−6−3−x0−8x2−2x80]A = \begin{bmatrix}0 & x^2-6 & -3\\-x & 0 & -8\\x^2-2x & 8 & 0\end{bmatrix}

For A to be skew-symmetric, the following conditions must hold:

a12=−a21a_{12} = -a_{21}

a13=−a31a_{13} = -a_{31}

a23=−a32a_{23} = -a_{32}


From a12=−a21a_{12} = -a_{21}:

x2−6=−(−x)x^2 - 6 = -(-x)

x2−6=xx^2 - 6 = x

x2−x−6=0x^2 - x - 6 = 0

(x−3)(x+2)=0(x - 3)(x + 2) = 0

x=3x = 3 or x=−2x = -2


From a13=−a31a_{13} = -a_{31}:

−3=−(x2−2x)-3 = -(x^2 - 2x)

−3=−x2+2x-3 = -x^2 + 2x

x2−2x−3=0x^2 - 2x - 3 = 0

(x−3)(x+1)=0(x - 3)(x + 1) = 0

x=3x = 3 or x=−1x = -1


From a23=−a32a_{23} = -a_{32}:

−8=−(8)-8 = -(8)

−8=−8-8 = -8

This condition is always satisfied.


For the matrix to be skew-symmetric, all three conditions must be satisfied simultaneously.

From the first condition: x=3x = 3 or x=−2x = -2

From the second condition: x=3x = 3 or x=−1x = -1

The only value common to both conditions is x=3x = 3.

Therefore, the correct answer is (A) only.

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