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The interval in which the function f(x)=2x3−3x2−36x+7f(x) = 2x^3 - 3x^2 - 36x + 7 is strictly decreasing is :

Solution

✅ Correct Option: 2

f′(x)=6x2−6x−36=6(x−3)(x+2)f'(x) = 6x^2 - 6x - 36 = 6(x-3)(x+2). f′(x)<0f'(x) < 0 when −2<x<3-2 < x < 3. Hence strictly decreasing on (−2,3)(-2, 3).

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