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The degree of the differential equation [1+(dydx)]3=(d2ydx2)2\left[1 + \left(\frac{dy}{dx}\right)\right]^3 = \left(\frac{d^2 y}{dx^2}\right)^2 is :

Solution

✅ Correct Option: 2

The given equation is already polynomial in derivatives. Highest order is d2ydx2\frac{d^2 y}{dx^2} and its highest power is 2, so degree =2= 2.

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