Skip to main contentSkip to solution

If X has a Poisson distribution such that P(X=1)=P(X=2)P(X = 1) = P(X = 2) then P(X=3)P(X = 3) is :

Solution

✅ Correct Option: 1

P(X=1)=P(X=2)P(X=1) = P(X=2): λe−λ=λ22e−λ\lambda e^{-\lambda} = \frac{\lambda^2}{2}e^{-\lambda}, so λ=2\lambda = 2. Then P(X=3)=23e−23!=86e−2=43e−2P(X=3) = \frac{2^3 e^{-2}}{3!} = \frac{8}{6}e^{-2} = \frac{4}{3}e^{-2}.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question