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The rate of change in area of a triangle having sides 10 cm and 12 cm when the variable angle between them is θ=60°\theta = 60°, is :

Solution

✅ Correct Option: 1

Area A=12(10)(12)sin⁡θ=60sin⁡θA = \frac{1}{2}(10)(12)\sin\theta = 60\sin\theta. dAdθ=60cos⁡θ\frac{dA}{d\theta} = 60\cos\theta. At θ=60∘\theta = 60^\circ: dAdθ=60×12=30\frac{dA}{d\theta} = 60 \times \frac{1}{2} = 30 cm2^2/radian.

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