Match List - I with List - II., List - I, List - II, (A) If A and B are mutually exclusive events, then P(A B) =, (I) (P(A B))/(P(B)), P(B) ≠ 0, (B) If A and B are independent events, then P(A B) =, (II) (P(A B))/(P(A)), P(A) ≠ 0, (C) If A and B are two events of a sample space of an experiment, then P(A/B) =, (III) P(A) * P(B), (D) If A and B are two events of a sample space of an experiment, then P(B/A) =, (IV) P(A) + P(B), Choose the correct answer from the options given below :

Question

Match List - I with List - II. | List - I | List - II | |---|---| | (A) If A and B are mutually exclusive events, then $$P(A \cup B) =$$ | (I) $$\frac{P(A \cap B)}{P(B)}, P(B) 
eq 0$$ | | (B) If A and B are independent events, then $$P(A \cap B) =$$ | (II) $$\frac{P(A \cap B)}{P(A)}, P(A) 
eq 0$$ | | (C) If A and B are two events of a sample space of an experiment, then $$P(A/B) =$$ | (III) $$P(A) \cdot P(B)$$ | | (D) If A and B are two events of a sample space of an experiment, then $$P(B/A) =$$ | (IV) $$P(A) + P(B)$$ | Choose the correct answer from the options given below :

Accepted Answer

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Answer

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Answer

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Answer

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

List - I	List - II
(A) If A and B are mutually exclusive events, then $P(A \cup B) =$	(I) $\frac{P(A \cap B)}{P(B)}, P(B) \neq 0$
(B) If A and B are independent events, then $P(A \cap B) =$	(II) $\frac{P(A \cap B)}{P(A)}, P(A) \neq 0$
(C) If A and B are two events of a sample space of an experiment, then $P(A/B) =$	(III) $P(A) \cdot P(B)$
(D) If A and B are two events of a sample space of an experiment, then $P(B/A) =$	(IV) $P(A) + P(B)$

Solution

Related questions:

Keyboard Shortcuts

CUET Mathematics Past Year Questions (Topic-Wise)