The number of diagonals in a Hexagon is:

A hexagon is a 6-sided polygon with 6 vertices and 6 sides.

A diagonal is a line that connects two non-adjacent vertices. The sides of the hexagon are not diagonals.

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For any polygon with $n$ sides, the number of diagonals is:

Number of Diagonals $= \dfrac{n(n-3)}{2}$

For a hexagon, $n = 6$:

Number of Diagonals $= \dfrac{6(6-3)}{2}$

$= \dfrac{6(3)}{2}$

$= \dfrac{18}{2}$

$= 9$

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From any vertex, lines can be drawn to other vertices:

Total vertices $= 6$

Excluding the vertex itself $= 6 - 1 = 5$

Excluding the 2 adjacent vertices (which form sides, not diagonals) $= 5 - 2 = 3$ diagonals per vertex

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Total lines from all 6 vertices:

$6 \times 3 = 18$

Each diagonal is counted twice (once from each endpoint):

Actual number of diagonals $= \dfrac{18}{2} = 9$

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Therefore, the number of diagonals in a hexagon is $9$.