The distance between points P(1, 2) and Q(-3, 6) is Option 1: 4√2 Option 2: 5√2 Option 3: √33 Option 4: √16

Answer: 4√2. Solution: Using the distance formula, PQ = √((-3-1)^2 + (6-2)^2) = √(16+16) = √32 = 4√2.

Geometry

Miscellaneous

Easy

The distance between points P(1, 2) and Q(-3, 6) is

$4\sqrt{2}$

$5\sqrt{2}$

$\sqrt{33}$

$\sqrt{16}$

✅ Correct Option: 1

Using the distance formula, $PQ = \sqrt{(-3-1)^2 + (6-2)^2} = \sqrt{16+16} = \sqrt{32} = 4\sqrt{2}$ .

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