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The point (x, y) is equidistant from the points (2, 4) and (1, 8). Find the relation between x and y.

Solution

✅ Correct Option: 1

Equating squared distances, (x−2)2+(y−4)2=(x−1)2+(y−8)2(x-2)^2 + (y-4)^2 = (x-1)^2 + (y-8)^2. Expanding gives −4x+20−8y=−2x+65−16y-4x + 20 - 8y = -2x + 65 - 16y, so −2x+8y=45-2x + 8y = 45, that is 2x−8y=−452x - 8y = -45.

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