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If the distance between the points (2, -2) and (5, k) is 5 units, then one of the possible values of k shall be which of the following?

Solution

✅ Correct Option: 3

The distance between points (2, -2) and (5, k) is 5 units.

Using the distance formula:

Distance=(x2−x1)2+(y2−y1)2\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

5=(5−2)2+(k−(−2))25 = \sqrt{(5 - 2)^2 + (k - (-2))^2}

5=(3)2+(k+2)25 = \sqrt{(3)^2 + (k + 2)^2}

5=9+(k+2)25 = \sqrt{9 + (k + 2)^2}


Squaring both sides:

25=9+(k+2)225 = 9 + (k + 2)^2

(k+2)2=16(k + 2)^2 = 16


Taking the square root of both sides:

k+2=±4k + 2 = \pm 4

This gives two possible values:

k+2=4k + 2 = 4

k=2k = 2

or

k+2=−4k + 2 = -4

k=−6k = -6


The possible values of k are 2 and -6.

Therefore, one of the possible values of k is 2.

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