CUET General Test: Quantitative ReasoningProgression & Series. Free, no login required.

Q1:

2025: 3 June Shift 2

Progression & Series

Easy

Consider the Arithmetic Progression: 3,8,13,18..... . What is the 18th term of the given Arithmetic Progression.

Choose the correct answer from the options given below:

Answer options
Option 2
Correct Answer
Explanation for 2025: 3 June Shift 2 GET question 1

Q2:

2025: 3 June Shift 1

Progression & Series

Medium

How many terms of the AP: 24, 21, 18, ............ must be taken so that their sum is 78?

Answer options
Option 3
Correct Answer
Explanation for 2025: 3 June Shift 1 GET question 2

Q3:

2025: 2 June Shift 2

Progression & Series

Easy

Solve the given equation by replacing the question mark "?" with the most appropriate option:

162+82−16∗8= ?16^2 + 8^2 - 16 * 8 = \ ?

Answer options
Option 3
Correct Answer
Explanation for 2025: 2 June Shift 2 GET question 3

Q4:

2025: 29 May Shift 2

Progression & Series

Medium

The 21st and 33rd terms of an arithmetic progression are 91 and 145 respectively. What is the 29th term?

Answer options
Option 1
Correct Answer
Explanation for 2025: 29 May Shift 2 GET question 4

Q5:

2025: 29 May Shift 1

Progression & Series

Medium

The first and the last terms of an arithmetic progression are 25 and 180, respectively. If the sum of all the terms is 1025, how many terms are there?

Answer options
Option 1
Correct Answer
Explanation for 2025: 29 May Shift 1 GET question 5

Q6:

2025: 27 May Shift 1

Progression & Series

Medium

The sum of n terms of the series

1+32+2+52+3+72+...1 + \frac{3}{2} + 2 + \frac{5}{2} + 3 + \frac{7}{2} + ...

Answer options
Option 2
Correct Answer
Explanation for 2025: 27 May Shift 1 GET question 6

Q7:

2025: 26 May Shift 1

Progression & Series

Medium

The value of

13×7+17×11+111×15+...+127×31\frac{1}{3 \times 7} + \frac{1}{7 \times 11} + \frac{1}{11 \times 15} + ... + \frac{1}{27 \times 31} is:

Answer options
Option 2
Correct Answer
Explanation for 2025: 26 May Shift 1 GET question 7

Q8:

2025: 24 May Shift 2

Progression & Series

Medium

If the third and ninth terms of an A.P. are 1 and 19 respectively, then the 23rd term will be:

Answer options
Option 2
Correct Answer
Explanation for 2025: 24 May Shift 2 GET question 8

Q9:

2025: 23 May Shift 1

Progression & Series

Medium

Which of the following list of numbers forms an arithmetic progression?

(A) 1, -1,-3 -5, .......

(B) -1.2, -3.2, -5.2, -7.2, ...........

(C) -2, 2, -2, 2, -2, ........

(D) 2, 52\frac{5}{2}, 3, 72\frac{7}{2} ......

Choose the correct answer from the options given below:

Answer options
Option 1
Correct Answer
Explanation for 2025: 23 May Shift 1 GET question 9

Q10:

2025: 22 May Shift 1

Progression & Series

Easy

In arithmetic progression(A.P.), the first term is 7 and the 6th term is 22. The sum of the first 10 terms of A.P. is:

Answer options

Q11:

2025: 21 May Shift 1

Progression & Series

Medium

In an arithmetic progression, if 6 is the third term, the ninth term exceeds the seventh term by 3, then 12 is which term?

Answer options

Q12:

2025: 20 May Shift 1

Progression & Series

Medium

In an A.P, if mthm^{th} term is n and the nthn^{th} term is m, where m≠nm \neq n, find the pthp^{th} term.

Answer options

Q14:

2025: 19 May Shift 1

Progression & Series

Medium

If the 5th and 9th terms of an arithmetic progression are 7 and 13, respectively, then the 15th term is:

Answer options

Q15:

2025: 16 May Shift 1

Progression & Series

Medium

The 7th and 9th terms of an arithmetic progression are 10 and 11, respectively. Find the 15th term.

Answer options

Q16:

2025: 15 May Shift 1

Progression & Series

Medium

If the sum of n terms of an A.P. is nP+12n(n−1)QnP + \frac{1}{2}n(n - 1)Q, where P and Q are constants, find the common difference.

Answer options

Q17:

2025: 14 May Shift 2

Progression & Series

Medium

Find the sum of 24 terms of the list of numbers whose nth^{th} term is given by:

an=3+2na_n = 3 + 2n

Answer options

Q18:

2025: 14 May Shift 1

Progression & Series

Medium

The sum of n terms of the series 1+1.5+2+2.5+3+...1 + 1.5 + 2 + 2.5 + 3 + ... is?

Answer options

Q19:

2025: 13 May Shift 2

Progression & Series

Medium

If each term of a geometric progression (GP) is positive and is the sum of two preceding terms, then the common ratio of the GP is:

Answer options