Q1:
2026: 6 June Shift 1
Arithmetic
Central Tendency
Medium
If the median of x/5, x/4, x/2, x and x/3, where x > 0, is 8, find the value of x.
2026: 6 June Shift 1
Arithmetic
Central Tendency
Medium
If the median of x/5, x/4, x/2, x and x/3, where x > 0, is 8, find the value of x.
2026: 31 May Shift 2
Arithmetic
Central Tendency
Easy
The mean of 30 observations was 15. Upon checking, it was found that two observations were wrongly taken as 2 and 5. If incorrect observations are replaced by the corrected values 7 and 11, then the corrected mean is?
2026: 31 May Shift 1
Arithmetic
Central Tendency
Easy
Match the LIST-I with LIST-II
| LIST-I (Measure of Dispersion) | LIST-II (Property of the Measure of Dispersion) |
|---|---|
| A. Range | I. Based on absolute deviation from mean or median |
| B. Variance | II. Based on squared deviation from mean |
| C. Standard Deviation | III. Square of standard deviation |
| D. Mean Deviation | IV. Difference between largest and smallest values |
Choose the correct answer from the options given below:
2026: 30 May Shift 2
Arithmetic
Central Tendency
Easy
The wicket taken by a bowler in 10 cricket matches are as follows:
2 6 4 5 0 2 1 3 2 3
Find the mode of the data.
2026: 30 May Shift 1
Arithmetic
Central Tendency
Medium
The median of the frequency distribution:
| Marks | Number of students |
|---|---|
| 0-5 | 7 |
| 5-10 | 5 |
| 10-15 | 2 |
| 15-20 | 4 |
| 20-25 | 1 |
| 25-30 | 6 |
| 30-35 | 3 |
| 35-40 | 8 |
| 40-45 | 9 |
| 45-50 | 5 |
2026: 29 May Shift 2
Arithmetic
Central Tendency
Easy
Salma bought 65 books for ₹ 1050 from one shop and 50 books for ₹ 1020 from another. What is the mean price she paid per book?
2026: 29 May Shift 1
Arithmetic
Central Tendency
Easy
The average marks of the students of a class are 55. What is the number of students in the class if the sum total of marks of all the students in the class is 3575 ?
2026: 26 May Shift 1
Arithmetic
Central Tendency
Medium
The median of frequency distribution is:
| Class : | 0 – 25 | 25 – 50 | 50 – 75 | 75 – 100 |
|---|---|---|---|---|
| Frequency : | 23 | 32 | 15 | 12 |
2026: 25 May Shift 2
Arithmetic
Central Tendency
Easy
The median of numbers 14, 7, 18, 21 and 27 is:
2026: 25 May Shift 2
Arithmetic
Central Tendency
Medium
The mean of 40 observations was 34. Upon checking, it was found that two observations were wrongly copied as 4 and 7. If incorrect observations are replaced by the corrected values 11 and 13, then find the corrected mean.
2026: 24 May Shift 1
Arithmetic
Central Tendency
Easy
The total sum in marks for 50 students in a class is 2250. Find the average marks in the class.
2026: 22 May Shift 2
Arithmetic
Central Tendency
Easy
For a certain distribution, mode and median were found to be 1000 and 1250 respectively. Find the mean of this distribution using an empirical relation.
2026: 21 May Shift 2
Arithmetic
Central Tendency
Easy
Heights (in cm) of 15 students are:
142, 145, 148, 150, 152, 155, 148, 150, 150, 152, 155, 148, 150, 152, 148.
What is the median height of the students?
2026: 21 May Shift 1
Arithmetic
Central Tendency
Medium
Find the mean deviation about the median for the following data set:
3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21.
2026: 20 May Shift 2
Arithmetic
Central Tendency
Medium
The following are the marks obtained in a class test by a student: 10, 12, 15, 15, 18, 20, 20, 20, 23. The variance is?
2026: 20 May Shift 1
Arithmetic
Central Tendency
Easy
If the mode of any data is 36.8 and the mean is 35.37, then the value of median is:
2026: 19 May Shift 2
Arithmetic
Central Tendency
Easy
The following table shows the ages of the patients admitted in a hospital during a year:
| Age (in year) | 5-15 | 15-25 | 25-35 | 35-45 | 45-55 | 55-65 |
|---|---|---|---|---|---|---|
| Number of patients | 6 | 11 | 19 | 23 | 14 | 7 |
Find the mean of the above data.
2026: 19 May Shift 1
Arithmetic
Central Tendency
Medium
The median of class frequency distribution is:
| Class: | 0 - 25 | 25 - 50 | 50 - 75 | 75 - 100 | Total |
|---|---|---|---|---|---|
| Frequency: | 25 | 32 | 15 | 16 | 88 |
2026: 18 May Shift 2
Arithmetic
Central Tendency
Easy
The mean of 5 numbers is 15. If one more number is included, the mean of the 6 numbers becomes 17. Find the included number.
2026: 18 May Shift 1
Arithmetic
Central Tendency
Medium
For the data set: 5, 7, 9, 11, 13, the standard deviation is:
2026: 14 May Shift 2
Arithmetic
Central Tendency
Easy
In a class of 30 students, 10 scored 40, 12 scored 50, 8 scored 60. The mean score is:
2026: 14 May Shift 1
Arithmetic
Central Tendency
Easy
The relation between Mean, Median and Mode is:
2026: 14 May Shift 1
Arithmetic
Central Tendency
Medium
The A.M.(Arithmetic Mean) and G.M (Geometric Mean) of two positive numbers p and q are 8 and 4 respectively, then the value of p - q are
2026: 12 May Shift 2
Arithmetic
Central Tendency
Easy
The mean of 50 observations was 46. Upon checking, it was found that two observations were wrongly copied as 5 and 8. If incorrect observations are replaced by the corrected values 12 and 14, then find the corrected mean.
2026: 12 May Shift 1
Arithmetic
Central Tendency
Hard
The median of the following frequency distribution is 52. If the total frequency is 50, the values of x and y are:
| Class Interval | Class Frequency |
|---|---|
| 0-10 | 1 |
| 10-20 | 3 |
| 20-30 | x |
| 30-40 | 6 |
| 40-50 | 5 |
| 50-60 | 8 |
| 60-70 | y |
| 70-80 | 7 |
| 80-90 | 5 |
| 90-100 | 3 |
2025: 3 June Shift 2
Arithmetic
Central Tendency
Easy
If the mean of five observations x + 1, x + 2, x + 3, x + 4 and x + 5 is 15, then what is the mean of the first three observations?
2025: 3 June Shift 1
Arithmetic
Central Tendency
Medium
In a class, the number of students who scored 61 or more marks is 30 and there are almost 39 students who have scored below 61 marks.
If the average marks of the class is 48, then determine that what is the largest possible average marks of students who have scored below 61 marks?
2025: 3 June Shift 1
Arithmetic
Central Tendency
Medium
Dittee has 10 purses and each of which having an average of 25 lipsticks in each purse. Further, it is known that each purse has a minimum of 8 lipsticks and none of the purse has identical number of lipsticks.
Determine that what can be the maximum number of lipsticks that Dittee shall have in any of her purse?
2025: 3 June Shift 1
Arithmetic
Central Tendency
Medium
Consider the following frequency distribution.
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
|---|---|---|---|---|---|---|---|
| Frequency | 4 | 5 | 7 | 10 | 12 | 8 | 4 |
Find the median of the distribution?
2025: 30 May Shift 2
Arithmetic
Central Tendency
Easy
Match List I with List II
| List I | List II |
|---|---|
| Statistical Measure | Definition |
| (A) Mode | (I) Sum of all observations divided by their count |
| (B) Median | (II) Measure of the spread from the mean |
| (C) Mean | (III) Central value when observations are arranged in order |
| (D) Standard Deviation | (IV) Observation which has the highest frequency |
Choose the correct answer from the options given below: