CUET General Test: ArithmeticCentral Tendency. Free, no login required.

Q2:

2026: 31 May Shift 2

Central Tendency

Easy

The mean of 30 observations was 15. Upon checking, it was found that two observations were wrongly taken as 2 and 5. If incorrect observations are replaced by the corrected values 7 and 11, then the corrected mean is?

Answer options
Option 1
Correct Answer
Explanation for 2026: 31 May Shift 2 GET question 2

Q3:

2026: 31 May Shift 1

Central Tendency

Easy

Match the LIST-I with LIST-II

LIST-I (Measure of Dispersion)LIST-II (Property of the Measure of Dispersion)
A. RangeI. Based on absolute deviation from mean or median
B. VarianceII. Based on squared deviation from mean
C. Standard DeviationIII. Square of standard deviation
D. Mean DeviationIV. Difference between largest and smallest values

Choose the correct answer from the options given below:

Answer options
Option 4
Correct Answer
Explanation for 2026: 31 May Shift 1 GET question 3

Q4:

2026: 30 May Shift 2

Central Tendency

Easy

The wicket taken by a bowler in 10 cricket matches are as follows:

2 6 4 5 0 2 1 3 2 3

Find the mode of the data.

Answer options
Option 1
Correct Answer
Explanation for 2026: 30 May Shift 2 GET question 4

Q5:

2026: 30 May Shift 1

Central Tendency

Medium

The median of the frequency distribution:

MarksNumber of students
0-57
5-105
10-152
15-204
20-251
25-306
30-353
35-408
40-459
45-505
Answer options
Option 4
Correct Answer
Explanation for 2026: 30 May Shift 1 GET question 5

Q6:

2026: 29 May Shift 2

Central Tendency

Easy

Salma bought 65 books for ₹ 1050 from one shop and 50 books for ₹ 1020 from another. What is the mean price she paid per book?

Answer options
Option 1
Correct Answer
Explanation for 2026: 29 May Shift 2 GET question 6

Q7:

2026: 29 May Shift 1

Central Tendency

Easy

The average marks of the students of a class are 55. What is the number of students in the class if the sum total of marks of all the students in the class is 3575 ?

Answer options
Option 3
Correct Answer
Explanation for 2026: 29 May Shift 1 GET question 7

Q8:

2026: 26 May Shift 1

Central Tendency

Medium

The median of frequency distribution is:

Class :0 – 2525 – 5050 – 7575 – 100
Frequency :23321512
Answer options
Option 1
Correct Answer
Explanation for 2026: 26 May Shift 1 GET question 8

Q10:

2026: 25 May Shift 2

Central Tendency

Medium

The mean of 40 observations was 34. Upon checking, it was found that two observations were wrongly copied as 4 and 7. If incorrect observations are replaced by the corrected values 11 and 13, then find the corrected mean.

Answer options

Q12:

2026: 22 May Shift 2

Central Tendency

Easy

For a certain distribution, mode and median were found to be 1000 and 1250 respectively. Find the mean of this distribution using an empirical relation.

Answer options

Q13:

2026: 21 May Shift 2

Central Tendency

Easy

Heights (in cm) of 15 students are:

142, 145, 148, 150, 152, 155, 148, 150, 150, 152, 155, 148, 150, 152, 148.

What is the median height of the students?

Answer options

Q14:

2026: 21 May Shift 1

Central Tendency

Medium

Find the mean deviation about the median for the following data set:

3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21.

Answer options

Q15:

2026: 20 May Shift 2

Central Tendency

Medium

The following are the marks obtained in a class test by a student: 10, 12, 15, 15, 18, 20, 20, 20, 23. The variance is?

Answer options

Q16:

2026: 20 May Shift 1

Central Tendency

Easy

If the mode of any data is 36.8 and the mean is 35.37, then the value of median is:

Answer options

Q17:

2026: 19 May Shift 2

Central Tendency

Easy

The following table shows the ages of the patients admitted in a hospital during a year:

Age (in year)5-1515-2525-3535-4545-5555-65
Number of patients6111923147

Find the mean of the above data.

Answer options

Q18:

2026: 19 May Shift 1

Central Tendency

Medium

The median of class frequency distribution is:

Class:0 - 2525 - 5050 - 7575 - 100Total
Frequency:2532151688
Answer options

Q19:

2026: 18 May Shift 2

Central Tendency

Easy

The mean of 5 numbers is 15. If one more number is included, the mean of the 6 numbers becomes 17. Find the included number.

Answer options

Q23:

2026: 14 May Shift 1

Central Tendency

Medium

The A.M.(Arithmetic Mean) and G.M (Geometric Mean) of two positive numbers p and q are 8 and 4 respectively, then the value of p - q are

Answer options

Q24:

2026: 12 May Shift 2

Central Tendency

Easy

The mean of 50 observations was 46. Upon checking, it was found that two observations were wrongly copied as 5 and 8. If incorrect observations are replaced by the corrected values 12 and 14, then find the corrected mean.

Answer options

Q25:

2026: 12 May Shift 1

Central Tendency

Hard

The median of the following frequency distribution is 52. If the total frequency is 50, the values of x and y are:

Class IntervalClass Frequency
0-101
10-203
20-30x
30-406
40-505
50-608
60-70y
70-807
80-905
90-1003
Answer options

Q26:

2025: 3 June Shift 2

Central Tendency

Easy

If the mean of five observations x + 1, x + 2, x + 3, x + 4 and x + 5 is 15, then what is the mean of the first three observations?

Answer options

Q27:

2025: 3 June Shift 1

Central Tendency

Medium

In a class, the number of students who scored 61 or more marks is 30 and there are almost 39 students who have scored below 61 marks.

If the average marks of the class is 48, then determine that what is the largest possible average marks of students who have scored below 61 marks?

Answer options

Q28:

2025: 3 June Shift 1

Central Tendency

Medium

Dittee has 10 purses and each of which having an average of 25 lipsticks in each purse. Further, it is known that each purse has a minimum of 8 lipsticks and none of the purse has identical number of lipsticks.

Determine that what can be the maximum number of lipsticks that Dittee shall have in any of her purse?

Answer options

Q29:

2025: 3 June Shift 1

Central Tendency

Medium

Consider the following frequency distribution.

Class0-1010-2020-3030-4040-5050-6060-70
Frequency457101284

Find the median of the distribution?

Answer options

Q30:

2025: 30 May Shift 2

Central Tendency

Easy

Match List I with List II

List IList II
Statistical MeasureDefinition
(A) Mode(I) Sum of all observations divided by their count
(B) Median(II) Measure of the spread from the mean
(C) Mean(III) Central value when observations are arranged in order
(D) Standard Deviation(IV) Observation which has the highest frequency

Choose the correct answer from the options given below:

Answer options