The relation between Mean, Median and Mode for symmetrical distribution is:

A symmetrical distribution has data spread equally on both sides of the center. The graph forms a mirror image, where the left side reflects the right side.

In a symmetrical distribution:

$\text{Mean} = \text{Median} = \text{Mode}$

All three measures of central tendency are located at the exact center of the distribution.

The mode represents the most frequently occurring value. In a symmetrical distribution, the highest point (peak) occurs at the center, making the mode the central value.

The median is the middle value when data is arranged in order. Since the distribution is perfectly balanced, the median lies at the center.

The mean is the average of all values. With values equally spread on both sides, they balance perfectly, placing the mean at the center.

Checking the given options:

Option 1: $\text{Mode} = 2\text{Median} - 5\text{Mean}$ does not apply to symmetrical distributions.

Option 2: $\text{Mode} = 4\text{Median} - \text{Mean}$ applies to skewed distributions, not symmetrical ones.

Option 3: $\text{Mean} = \text{Median} = \text{Mode}$ is the correct relationship.

Option 4: $\text{Mode} = 2\text{Median} = \text{Mean}$ would require Mode $= 2$Median and $2$Median $= \text{Mean}$, which is inconsistent with symmetrical distributions.

The answer is Option 3: $\text{Mean} = \text{Median} = \text{Mode}$