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If the point A (0, 2) is equidistant from the points B (3, p) and C (p, 5), the value of p is :

Solution

✅ Correct Option: 1

Equate squared distances: AB2=9+(p−2)2AB^2 = 9 + (p-2)^2 and AC2=p2+9AC^2 = p^2 + 9. So 9+p2−4p+4=p2+99 + p^2 - 4p + 4 = p^2 + 9, which reduces to 4p=44p = 4, giving p=1p = 1.

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