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Jatin is ninth from the front in a column of boys. There were thrice as many behind him as there were in front. How many boys are there between Jatin and the fifth boy from the end of the column?

Solution

✅ Correct Option: 4

Jatin is 9th from the front, so there are 8 boys in front of him.

Let the total number of boys be nn.

The number of boys behind Jatin =n−9= n - 9

Given that there were thrice as many behind him as in front:

n−9=3×8n - 9 = 3 \times 8

n−9=24n - 9 = 24

n=33n = 33

Therefore, there are 33 boys in total.


The fifth boy from the end is at position:

Position from front =33−5+1=29= 33 - 5 + 1 = 29

So the fifth boy from the end is 29th from the front.


Jatin is at position 9 from the front.

The fifth boy from the end is at position 29 from the front.

Number of boys between them =29−9−1=19= 29 - 9 - 1 = 19

Therefore, there are 19 boys between Jatin and the fifth boy from the end.

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