d:[["$","title","0",{"children":"JIPMAT - If the eight-digit number 5a32465b is divisible by 88, then 2a+ 5b = | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined Let me solve this carefully: For divisibility by 88 (= 8 × 11): Number must be divisib<= by both 8 and 11 1) For divisibility by 8: - Last three digits (65b) must be divisib<= by 8 - Testing values: b = 6 makes 656 divisib<= by 8 2) For divisibility by 11: - Difference of sums of alternate digits must be divisib<= by 11 - (5+3+4+5)-(a+2+6+6)=17-14-a - (3 - a) must be divisib<= by 11 - Therefore a = 3 So the number is 5332465b where b = 6 2a + 5b = 2(3) + 5(6) = 6 + 30 = 36"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"JIPMAT,QA,Number System,Divisibility Rules"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"JIPMAT - If the eight-digit number 5a32465b is divisible by 88, then 2a+ 5b = | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined Let me solve this carefully: For divisibility by 88 (= 8 × 11): Number must be divisib<= by both 8 and 11 1) For divisibility by 8: - Last three digits (65b) must be divisib<= by 8 - Testing values: b = 6 makes 656 divisib<= by 8 2) For divisibility by 11: - Difference of sums of alternate digits must be divisib<= by 11 - (5+3+4+5)-(a+2+6+6)=17-14-a - (3 - a) must be divisib<= by 11 - Therefore a = 3 So the number is 5332465b where b = 6 2a + 5b = 2(3) + 5(6) = 6 + 30 = 36"}],["$","meta","9",{"property":"og:url","content":"https://www.afterboards.in/past-year-questions/jipmat/2023/QA/15"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | JIPMAT Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"JIPMAT - If the eight-digit number 5a32465b is divisible by 88, then 2a+ 5b = | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined Let me solve this carefully: For divisibility by 88 (= 8 × 11): Number must be divisib<= by both 8 and 11 1) For divisibility by 8: - Last three digits (65b) must be divisib<= by 8 - Testing values: b = 6 makes 656 divisib<= by 8 2) For divisibility by 11: - Difference of sums of alternate digits must be divisib<= by 11 - (5+3+4+5)-(a+2+6+6)=17-14-a - (3 - a) must be divisib<= by 11 - Therefore a = 3 So the number is 5332465b where b = 6 2a + 5b = 2(3) + 5(6) = 6 + 30 = 36"}],["$","meta","17",{"name":"twitter:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","link","18",{"rel":"shortcut icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","19",{"rel":"icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","20",{"rel":"icon","href":"https://www.afterboards.in/icons/windows11/Square44x44Logo.altform-lightunplated_targetsize-256.png","sizes":"256x256","type":"image/png"}],["$","link","21",{"rel":"icon","href":"https://www.afterboards.in/icons/android/android-launchericon-512-512.png","sizes":"512x512","type":"image/png"}],"$L16","$L17","$L18","$L19","$L1a"]

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