CUET Mathematics: CalculusApplication of Derivatives. Free, no login required.

Q1:

2025: 26 May Shift 2

Application of Derivatives

Medium

Applied

The volume of spherical balloon is increasing at the rate of 4 cm3/sec4 \text{ cm}^3/ \text{sec}. The rate of increase of its surface area, when the radius is 3cm will be :-

Answer options
Option 2
Correct Answer
Explanation for 2025: 26 May Shift 2 MAT question 1

Q2:

2025: 26 May Shift 2

Application of Derivatives

Medium

Applied

The interval(s), where the function f(x)={1−exe2x−1:x≠0−12:x=0f(x) = \begin{cases} \frac{1-e^x}{e^{2x}-1} & : x \neq 0 \\ \frac{-1}{2} & : x = 0 \end{cases} is increasing, is/ are:

Answer options
Option 3
Correct Answer
Explanation for 2025: 26 May Shift 2 MAT question 2

Q3:

2025: 26 May Shift 2

Application of Derivatives

Medium

Applied

A square board of side 36cm is made into a box without top by cutting a square from each corner and folding up the flaps to form a box then maximum volume of the box is

Answer options
Option 4
Correct Answer
Explanation for 2025: 26 May Shift 2 MAT question 3

Q4:

2025: 22 May Shift 2

Application of Derivatives

Medium

Common

The largest interval, in which the function f(x)=x3+2x2−1f(x) = x^3 + 2x^2 - 1 is increasing, is:

Answer options
Option 4
Correct Answer
Explanation for 2025: 22 May Shift 2 MAT question 4

Q5:

2025: 22 May Shift 2

Application of Derivatives

Medium

Common

The maximum value of (1x)x\left(\frac{1}{x}\right)^x for x>0x > 0 is

Answer options
Option 2
Correct Answer
Explanation for 2025: 22 May Shift 2 MAT question 5

Q6:

2025: 22 May Shift 2

Application of Derivatives

Medium

Core

A boat 10 m high floating at a uniform speed of 13 meters per minute(m/min) away from a lamp post 15 m high. Then the rate at which the length of shadow of the boat increases is:

Answer options
Option 1
Correct Answer
Explanation for 2025: 22 May Shift 2 MAT question 6

Q7:

2025: 22 May Shift 2

Application of Derivatives

Medium

Core

If the function f(x)=2x2−kx+7f(x) = 2x^2 - kx + 7, is increasing on [1,2][1,2], then kk lies in the interval

Answer options
Option 2
Correct Answer
Explanation for 2025: 22 May Shift 2 MAT question 7

Q8:

2025: 22 May Shift 2

Application of Derivatives

Medium

Applied

Which of the following statements are true?

(A) The function f(x)=x44−43x3+x22+6xf(x) = \frac{x^4}{4} - \frac{4}{3}x^3 + \frac{x^2}{2} + 6x has 3 critical points.

(B) The function f(x)=∣x∣+3f(x) = |x| + 3 has no minimum value.

(C) A local maximum value is always the absolute maximum value.

(D) f(x)=x2f(x) = x^2 has minima at x=0x=0.

Choose the correct answer from the options given below:

Answer options
Option 3
Correct Answer
Explanation for 2025: 22 May Shift 2 MAT question 8

Q9:

2025: 22 May Shift 2

Application of Derivatives

Easy

Applied

The rate of change of the area of a circle with respect to its radius rr, when r=3r = 3cm, is:

Answer options
Option 1
Correct Answer
Explanation for 2025: 22 May Shift 2 MAT question 9

Q10:

2025: 22 May Shift 2

Application of Derivatives

Medium

Applied

The curve x=y2x = y^2 and xy=kxy = k cut orthogonally, then k2k^2 is equal to:

Answer options

Q11:

2025: 22 May Shift 2

Application of Derivatives

Medium

Applied

Match List-I with List-II

List-IList-II
(A) Marginal average cost if cost function C(x)=50xC(x) = \frac{50}{\sqrt{x}}(I) 50x50\sqrt{x}
(B) Marginal average cost if cost function C(x)=50xC(x) = 50\sqrt{x}(II) −75x2x-\frac{75}{x^2\sqrt{x}}
(C) Revenue function if demand function P=50xP=\frac{50}{\sqrt{x}}(III) −25xx\frac{-25}{x\sqrt{x}}
(D) Marginal revenue if demand function P=50xP=50\sqrt{x}(IV) 75x75\sqrt{x}

Choose the correct answer from the options given below:

Answer options

Q12:

2025: 22 May Shift 1

Application of Derivatives

Medium

Common

The function f(x)=x2e−2xf(x) = x^2e^{-2x} increases on

Answer options

Q13:

2025: 22 May Shift 1

Application of Derivatives

Medium

Common

The function f(x)=−34x4−8x3−452x2+163f(x) = \frac{-3}{4}x^4 - 8x^3 - \frac{45}{2}x^2 + 163 has a local maxima at

Answer options

Q14:

2025: 22 May Shift 1

Application of Derivatives

Medium

Core

The rate of change of volume of a sphere with respect to its surface area, when radius is 4 cm, is equal to

Answer options

Q15:

2025: 22 May Shift 1

Application of Derivatives

Medium

Core

The function f(x)=log⁡e(sin⁡x),x∈(0,π)f(x) = \log_e(\sin x), x \in (0, \pi) is

(A) strictly increasing on (0,π2)\left(0, \frac{\pi}{2}\right)

(B) strictly decreasing on (0,π2)\left(0, \frac{\pi}{2}\right)

(C) strictly increasing on (π2,π)\left(\frac{\pi}{2}, \pi\right)

(D) strictly decreasing on (π2,π)\left(\frac{\pi}{2}, \pi\right)

(E) strictly increasing on (0,π)(0, \pi)

Choose the correct answer from the options given below:

Answer options

Q16:

2025: 22 May Shift 1

Application of Derivatives

Medium

Applied

The demand function for a certain product is represented by the equation: p=20+5x−3x2p = 20 + 5x - 3x^2, where xx is the number of units demanded and pp is the price per unit (in Rs.), then the marginal revenue when 2 units are sold is:

Answer options

Q17:

2025: 22 May Shift 1

Application of Derivatives

Medium

Applied

The equation of the tangent line to the curve y=x2−2x+5y = x^2 - 2x + 5 which is parallel to the line 4x−y+1=04x - y + 1 = 0 is

Answer options

Q18:

2025: 22 May Shift 1

Application of Derivatives

Medium

Applied

Match List-I with List-II

List-IList-II
FunctionIncreasing on the interval
(A) f(x)=−x2−2x+1f(x) = -x^2 - 2x + 1(I) (−∞,−1)(-\infty, -1)
(B) f(x)=x2+1f(x) = x^2 + 1(II) (1,∞)(1, \infty)
(C) f(x)=x2−2x+3f(x) = x^2 - 2x + 3(III) (−∞,0)(-\infty, 0)
(D) f(x)=−x2f(x) = -x^2(IV) (0,∞)(0, \infty)

Choose the correct answer from the options given below:

Answer options

Q19:

2025: 21 May Shift 2

Application of Derivatives

Medium

Common

The function f(x)=6−6x−2x2f(x) = 6 - 6x - 2x^2

Answer options

Q20:

2025: 21 May Shift 2

Application of Derivatives

Medium

Common

The function f(x)=x+1xf(x) = x + \frac{1}{x} has

Answer options

Q21:

2025: 21 May Shift 2

Application of Derivatives

Medium

Core

If the maximum value of the function f(x)=2log⁡exxf(x) = \frac{2\log_e x}{x}, x>0x > 0 occurs at x=ex = e, then e3f′′(e)e^3 f''(e) is equal to

Answer options

Q22:

2025: 21 May Shift 2

Application of Derivatives

Medium

Core

For the function f(x)=2x3−3x2−12x+5f(x) = 2x^3 - 3x^2 - 12x + 5, the difference of maximum and minimum value of f(x)f(x) is

Answer options

Q23:

2025: 21 May Shift 2

Application of Derivatives

Medium

Core

Interval in which the function ff given by f(x)=tan⁡x−4xf(x) = \tan x - 4x, x∈(0,π2)x \in (0, \frac{\pi}{2}) is strictly decreasing is

Answer options

Q24:

2025: 21 May Shift 2

Application of Derivatives

Medium

Applied

The marginal cost (MC) and marginal revenue (MR) functions of a product are MC=20+x20MC = 20 + \frac{x}{20} and MR=30MR = 30 respectively. If the fixed cost is 200, then the maximum value of the profit is:

Answer options

Q25:

2025: 21 May Shift 2

Application of Derivatives

Hard

Applied

For the function, f(x)=−34x4−8x3−452x2−350f(x) = \frac{-3}{4}x^4 - 8x^3 - \frac{45}{2}x^2 - 350, which of the following statements are correct?

(A) x=−3x = -3 and x=−5x = -5 are the only critical points of the given function.

(B) x=−3x = -3 is a point of local minimum.

(C) The local minimum value at x=−3x = -3 is 23.1.

(D) x=−5x = -5 is a point of local maximum.

Choose the correct answer from the options given below:

Answer options

Q26:

2025: 21 May Shift 2

Application of Derivatives

Medium

Applied

Match List-I with List-II

List-I (Curve)List-II (Slope of tangent at x=4x = 4)
(A) y=x3y = \sqrt{x^3}(I) -1
(B) y=xy = \sqrt{x}(II) 1
(C) y=x3−47xy = x^3 - 47x(III) 1/4
(D) xy=16xy = 16(IV) 3

Choose the correct answer from the options given below:

Answer options

Q27:

2025: 21 May Shift 1

Application of Derivatives

Medium

Common

The real valued function f(x)=x15+5x9+10f(x) = x^{15} + 5x^9 + 10 is increasing for___________.

Answer options

Q28:

2025: 21 May Shift 1

Application of Derivatives

Medium

Common

If y=ax2+bxy = ax^2 + bx has minima at x=2x = 2 and the minimum value is -12, then which of the following are correct?

(A) a=3a = 3

(B) a=−3a = -3

(C) b=12b = 12

(D) b=−12b = -12

Choose the correct answer from the options given below:

Answer options

Q29:

2025: 21 May Shift 1

Application of Derivatives

Medium

Core

Match List-I with List-II

List-IList-II
(A) Maximum value of f(x)=sin⁡2x−cos⁡2xf(x) = \sin^2 x - \cos^2 x, ∀x∈(π,2π)\forall x \in (\pi, 2\pi) is(I) 0
(B) Minimum value of f(x)=sin⁡xcos⁡xf(x) = \sin x \cos x(II) 1
(C) Point of Minima of f(x)=xxf(x) = x^x (x>0)(x > 0)(III) −12-\frac{1}{2}
(D) Maximum value of f(x)=−x2026f(x) = -x^{2026}(IV) 1e\frac{1}{e}

Choose the correct answer from the options given below:

Answer options

Q30:

2025: 21 May Shift 1

Application of Derivatives

Medium

Core

The interval in which the function f(x)=2x3+3x2−12x+1f(x) = 2x^3 + 3x^2 - 12x + 1 is strictly increasing, is

Answer options