CUET Mathematics: CalculusApplication of Derivatives. Free, no login required.

Q1:

2025: 30 May Shift 2

Application of Derivatives

Medium

Core

If the minimum value of aa is −k2-\frac{k}{2} such that the function f(x)=x2+ax+5f(x) = x^2 + ax + 5 is increasing in [1, 2]. Then value of kk is

Answer options
Option 3
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 1

Q2:

2025: 30 May Shift 2

Application of Derivatives

Medium

Core

A spherical ice ball is melting at the rate of 100 π\pi cm³/min. The rate at which its radius is decreasing when its radius is 15 cm, is

Answer options
Option 2
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 2

Q3:

2025: 30 May Shift 2

Application of Derivatives

Medium

Core

For the function f(x)=ex+e−xf(x) = e^x + e^{-x}

(A) f′(x)=ex−e−xf'(x) = e^x - e^{-x}

(B) The critical point is x=0x = 0

(C) The minimum value is 1

(D) x=0x = 0 is the point of local minimum.

Choose the correct answer from the options given below:

Answer options

Q4:

2025: 30 May Shift 2

Application of Derivatives

Medium

Applied

The equation of tangent line to y=2x2+7y = 2x^2 + 7, which is parallel to the line 4x−y+3=04x - y + 3 = 0 is

Answer options
Option 3
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 4

Q5:

2025: 30 May Shift 2

Application of Derivatives

Easy

Applied

If the cost function of a product is given by C(x)=34x2−5x+21C(x) = \frac{3}{4}x^2 - 5x + 21, then the marginal cost when x=10x = 10 is

Answer options
Option 1
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 5

Q6:

2025: 30 May Shift 2

Application of Derivatives

Easy

Applied

The function f:R→Rf: R \rightarrow R (where RR is set of real numbers) defined as

f(x)=x2+2xf(x) = x^2 + 2x is

Answer options
Option 1
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 6

Q7:

2025: 30 May Shift 1

Application of Derivatives

Medium

Common

The point of local maxima of the function f(x)=(x−2)5(x+2)2f(x) = (x - 2)^5(x + 2)^2 is

Answer options
Option 4
Correct Answer
Explanation for 2025: 30 May Shift 1 MAT question 7

Q8:

2025: 30 May Shift 1

Application of Derivatives

Medium

Common

A car is moving along the curve y=x3+12y = x^3 + 12. The point(s) on the curve at which the rate of change of its y-coordinate at a certain time is 3 times the rate of change of its x-coordinate is/are

Answer options
Option 3
Correct Answer
Explanation for 2025: 30 May Shift 1 MAT question 8

Q9:

2025: 30 May Shift 1

Application of Derivatives

Medium

Core

The rate of change of area of a circle with respect to its circumference when radius in 6 cm, is

Answer options
Option 3
Correct Answer
Explanation for 2025: 30 May Shift 1 MAT question 9

Q10:

2025: 30 May Shift 1

Application of Derivatives

Easy

Core

Match List-I with List-II

List-IList-II
(A) The maximum value of f(x)=sin⁡(3x)+6f(x) = \sin(3x) + 6(I) 2
(B) The maximum value of f(x)=−∣x+2∣+4f(x) = -\vert x + 2\vert + 4(II) 5
(C) The minimum value of f(x)=(3x+1)2+5f(x) = (3x + 1)^2 + 5(III) 7
(D) The minimum value of f(x)=2cos⁡x+4f(x) = 2 \cos x + 4(IV) 4

Choose the correct answer from the options given below:

Answer options

Q11:

2025: 30 May Shift 1

Application of Derivatives

Medium

Core

The largest open interval, in which the function f(x)=xx2+1f(x) = \frac{x}{x^2 + 1} increases, is

Answer options

Q12:

2025: 30 May Shift 1

Application of Derivatives

Medium

Applied

The demand function (in Rs.) for a product is given by P=20−0.25xP = 20 - 0.25x, where P is the price per unit and x is the number of units sold, then the price of one unit, when the revenue is maximized, is:

Answer options

Q13:

2025: 29 May Shift 2

Application of Derivatives

Easy

Common

Match List-I with List-II

List-IList-II
Function f(x)Interval for increasing/decreasing of function f(x)
------
(A) f(x)=x∣x∣f(x) = x\vert x\vert (I) Decreases on (0,∞)(0, \infty)
(B) f(x)=x2+2x−5f(x) = x^2 + 2x - 5(II) Increases on (3,∞)(3, \infty)
(C) f(x)=x2−6x+9f(x) = x^2 - 6x + 9(III) Decreases on (−∞,−1)(-\infty, -1)
(D) f(x)=−x2f(x) = -x^2(IV) Increases on (−∞,∞)(-\infty, \infty)

Choose the correct answer from the options given below:

Answer options

Q14:

2025: 29 May Shift 2

Application of Derivatives

Medium

Common

If f(x)=2x3−15x2+36x+1f(x) = 2x^3 - 15x^2 + 36x + 1, x∈[1,5]x \in [1, 5], then the absolute minimum value of f(x)f(x) is:

Answer options

Q15:

2025: 29 May Shift 2

Application of Derivatives

Medium

Core

The rate of change of volume of a sphere with respect to its surface area, when the radius is 6cm is:

Answer options

Q16:

2025: 29 May Shift 2

Application of Derivatives

Easy

Core

The function f(x)=x2−x+1f(x) = x^2 - x + 1 is

Answer options

Q17:

2025: 29 May Shift 2

Application of Derivatives

Medium

Core

Let f(x)=4x3−18x2+27x−5f(x) = 4x^3 - 18x^2 + 27x - 5, x∈Rx \in R. Then which of the following statements are TRUE?

(A) f′′(x)=24x−36f''(x) = 24x - 36

(B) f has local maxima at x=32x = \frac{3}{2} but no minima

(C) f has neither maxima nor minima

(D) f has both maxima and minima

Choose the correct answer from the options given below:

Answer options

Q18:

2025: 29 May Shift 2

Application of Derivatives

Medium

Applied

The function f(x)=x3+3xf(x) = \frac{x}{3} + \frac{3}{x} is increasing in the interval:

Answer options

Q19:

2025: 29 May Shift 2

Application of Derivatives

Medium

Applied

The total cost function is given by c(x)=13x3−5x2+30x−15c(x) = \frac{1}{3}x^3 - 5x^2 + 30x - 15 and selling price per unit is Rs.6. The profit is maximum if the value of x is:

Answer options

Q20:

2025: 27 May Shift 1

Application of Derivatives

Medium

Common

The interval on which the function f(x)=x3+2x2−1f(x) = x^3 + 2x^2 - 1 is decreasing, is

Answer options

Q21:

2025: 27 May Shift 1

Application of Derivatives

Medium

Common

For the function f(x)=e−2x(2−x)2f(x) = e^{-2x}(2-x)^2, the point of local maxima is:

Answer options

Q22:

2025: 27 May Shift 1

Application of Derivatives

Medium

Core

For x∈Rx \in \mathbb{R}, if f(x)=−(x−1)2+2f(x) = -(x-1)^2 + 2, then

(A) ff is an increasing function on (−∞,1](-\infty, 1]

(B) ff has no critical points

(C) ff has a maximum value at x=1x = 1

(D) ff has a minimum value at x=1x = 1

Choose the correct answer from the options given below:

Answer options

Q23:

2025: 27 May Shift 1

Application of Derivatives

Medium

Core

A balloon which always remains spherical, has a variable diameter 32(5x+7)\frac{3}{2}(5x+7). Then the rate of change of its volume with respect to x is

Answer options

Q24:

2025: 27 May Shift 1

Application of Derivatives

Medium

Core

If f(x)=sin⁡x−cos⁡xf(x) = \sin x - \cos x, x∈[0,2π]x \in [0, 2\pi] then

(A) f(x)f(x) is increasing in (0,3π4)(0, \frac{3\pi}{4})

(B) f(x)f(x) is decreasing in (0,3π4)(0, \frac{3\pi}{4})

(C) f(x)f(x) is decreasing in (3π4,7π4)(\frac{3\pi}{4}, \frac{7\pi}{4})

(D) f(x)f(x) is decreasing in (7π4,2π)(\frac{7\pi}{4}, 2\pi)

Choose the correct answer from the options given below:

Answer options

Q25:

2025: 27 May Shift 1

Application of Derivatives

Medium

Applied

The largest open interval in which the function f(x)=4x3−5x2−8x+12f(x) = 4x^3 - 5x^2 - 8x + 12 increases, is:

Answer options

Q26:

2025: 27 May Shift 1

Application of Derivatives

Medium

Applied

A cylindrical drum of radius 7 cm and height 2 m is being kept in a vertical position filled with milk. If the milk is leaking at 14 cm³/sec from its lower base, then the rate of decrease in the level of milk is:

[Take π=227\pi = \frac{22}{7}]

Answer options

Q27:

2025: 26 May Shift 2

Application of Derivatives

Medium

Common

The function f(x)=x3+3x2+4x+4f(x) = x^3 + 3x^2 + 4x + 4, x∈Rx \in \mathbb{R} (set of real numbers) :

Answer options

Q28:

2025: 26 May Shift 2

Application of Derivatives

Medium

Common

The maximum value of the function f(x)=x2(60−x)f(x) = x^2(60 - x) in [20, 80] is:

Answer options

Q29:

2025: 26 May Shift 2

Application of Derivatives

Medium

Core

The edge of a cube is increasing at a rate of 7 cm/s. The rate of change of area of the cube when its side is 3 cm is:

Answer options

Q30:

2025: 26 May Shift 2

Application of Derivatives

Medium

Core

If it is given that at x=1x = 1, the function f(x)=x4−62x2+2ax+bf(x) = x^4 - 62x^2 + 2ax + b attains its maximum value on the interval [0, 2], then the value of a is:

Answer options