CUET Mathematics - A solid sphere of gold of radius 5 cm, is being melted in a furnace such that the radius is decreasing uniformly. When the radius is 1cm, the rate at which surface area (A) is decreasing w.r.t. time (t) is equal to (dv/dt = rate at which volume is decreasing w.r.t. t) | PYQs + Solutions | AfterBoards

CUET Mathematics 2026 18th May Shift 1 PYQs

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CUET Mathematics 2026 18th May Shift 1

Calculus

>

Medium

core

$\frac{dv}{dt}$

$\frac{2dv}{dt}$

$\frac{1}{2}\left(\frac{dv}{dt}\right)$

$3\left(\frac{dv}{dt}\right)$

✅ Correct Option: 2

Related questions:

15th May Shift 1

Match the LIST-I with LIST-II

	LIST-I		LIST-II
A.	$y = x^2$	I.	decreasing on $(0, \infty)$
B.	$y = -x^2$	II.	increasing on $(0, \infty)$
C.	$y = x$	III.	decreasing on $(-\infty, \infty)$
D.	$y = -x$	IV.	increasing on $(-\infty, \infty)$

Choose the correct answer from the options given below:

12th May Shift 2

If $x$ is real, then the minimum value of $x^2 - 8x + 25$ is

15 May Shift 1

The function $f(x) = x^2 - 4x + 6$ is

(A) Strictly decreasing on $(-\infty, 2) \cup (2, \infty)$

(B) Strictly increasing on $(2, \infty)$

(C) Strictly increasing on $(-\infty, \infty)$

(D) Strictly decreasing on $(-\infty, 2)$

Choose the correct answer from the options given below:

12th May Shift 2

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