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A bag contains 3 white and 2 black balls, another bag contains some white and 4 black balls. One bag is chosen at random. From the selected bag, one ball is drawn. If the probability of getting a black ball from the selected bag is 8/15, then the number of white balls in the second bag is

Solution

✅ Correct Option: 2

Let the second bag hold ww white balls.

12⋅25+12⋅4w+4=815\frac{1}{2}\cdot\frac{2}{5}+\frac{1}{2}\cdot\frac{4}{w+4} = \frac{8}{15}

2w+4=815−15=13⇒w+4=6⇒w=2\frac{2}{w+4} = \frac{8}{15}-\frac{1}{5} = \frac{1}{3} \Rightarrow w+4 = 6 \Rightarrow w = 2.

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