1/x^2+4x+8dx is equal to (Where C is an arbitrary constant) Option 1: -2^-1(x+2) Option 2: ^-1x+2/2 + C Option 3: -1/2^-1x+2/2 + C Option 4: 1/2^-1x+2/2 + C

The answer is '1/2^-1x+2/2 + C'. View full solution:

CUET Mathematics - 1/x^2+4x+8dx is equal to (Where C is an arbitrary constant) | PYQs + Solutions

CUET Mathematics 2026 18th May Shift 1

Calculus

Easy

core

$-2\tan^{-1}(x+2)$

$\tan^{-1}\frac{x+2}{2} + C$

$-\frac{1}{2}\tan^{-1}\frac{x+2}{2} + C$

$\frac{1}{2}\tan^{-1}\frac{x+2}{2} + C$

✅ Correct Option: 4