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A die is thrown and a coin is tossed. The probability that the outcome will be a number greater than 4 or a head or both is

Solution

✅ Correct Option: 1

P(number>4)=26=13P(\text{number}>4) = \frac{2}{6} = \frac{1}{3} and P(head)=12P(\text{head}) = \frac{1}{2}; the two are independent.

P(A∪B)=13+12−13⋅12=13+12−16=23P(A\cup B) = \frac{1}{3}+\frac{1}{2}-\frac{1}{3}\cdot\frac{1}{2} = \frac{1}{3}+\frac{1}{2}-\frac{1}{6} = \frac{2}{3}.

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