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The area of the region bounded by curves y=∣x−4∣y = |x-4|, x=1x = 1, x=5x = 5 and the x-axis is

Solution

✅ Correct Option: 3

Split at x=4x=4 where the modulus changes sign.

∫14(4−x)dx=92\int_1^4 (4-x)dx = \frac{9}{2} and ∫45(x−4)dx=12\int_4^5 (x-4)dx = \frac{1}{2}.

Total area =92+12=5=\frac{9}{2}+\frac{1}{2} = 5 square units.

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