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The interval in which the function f(x)=x3−3x2+3x−20f(x) = x^3-3x^2+3x-20 is increasing, is

Solution

✅ Correct Option: 1

f′(x)=3x2−6x+3=3(x−1)2≥0f'(x) = 3x^2-6x+3 = 3(x-1)^2 \geq 0 for every real xx, vanishing only at the single point x=1x=1.

Hence ff is increasing on (−∞,∞)(-\infty,\infty).

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