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If a⃗=i^+j^+2k^\vec a=\hat i+\hat j+2\hat k and b⃗=2i^+j^+2k^\vec b=2\hat i+\hat j+2\hat k, then the unit vector in the direction of 2a⃗−b⃗2\vec a-\vec b is equal to :

Solution

✅ Correct Option: 4

2a⃗−b⃗=(2−2)i^+(2−1)j^+(4−2)k^=j^+2k^2\vec a-\vec b=(2-2)\hat i+(2-1)\hat j+(4-2)\hat k=\hat j+2\hat k.

Its magnitude is 1+4=5\sqrt{1+4}=\sqrt5, so the unit vector is 15(j^+2k^)\frac{1}{\sqrt5}(\hat j+2\hat k).

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