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If y=log⁡xxy=\frac{\log x}{x}, then d2ydx2\frac{d^2y}{dx^2} is equal to(Consider log⁡ex=log⁡x\log_e x = \log x):

Solution

✅ Correct Option: 4

By the quotient rule, dydx=1−log⁡xx2\frac{dy}{dx}=\frac{1-\log x}{x^2}.

Differentiating again: d2ydx2=−x−2x(1−log⁡x)x4=−1−2+2log⁡xx3=2log⁡x−3x3\frac{d^2y}{dx^2}=\frac{-x-2x(1-\log x)}{x^4}=\frac{-1-2+2\log x}{x^3}=\frac{2\log x-3}{x^3}.

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