The relation between 'marginal cost (MC)' and 'average cost (AC)' of producing 'x' units of a product is Option 1: d/dx(AC)=x(MC-AC) Option 2: d/dx(AC)=x(AC-MC) Option 3: d/dx(AC)=1/x(AC-MC) Option 4: d/dx(AC)=1/x(MC-AC)

The answer is 'd/dx(AC)=1/x(MC-AC)'. View full solution:

CUET Mathematics - The relation between 'marginal cost (MC)' and 'average cost (AC)' of producing 'x' units of a product is | PYQs + Solutions

CUET Mathematics 2026 14th May Shift 2

Applied Mathematics

Medium

applied

$\frac{d}{dx}(AC)=x(MC-AC)$

$\frac{d}{dx}(AC)=x(AC-MC)$

$\frac{d}{dx}(AC)=\frac{1}{x}(AC-MC)$

$\frac{d}{dx}(AC)=\frac{1}{x}(MC-AC)$

✅ Correct Option: 4