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If ∣2451∣=∣2x46x∣\begin{vmatrix} 2 & 4 \\ 5 & 1 \end{vmatrix} = \begin{vmatrix} 2x & 4 \\ 6 & x \end{vmatrix}, then x is equal to :

Solution

✅ Correct Option: 3

LHS = 2(1)−4(5)=2−20=−182(1) - 4(5) = 2 - 20 = -18.

RHS = 2x⋅x−4⋅6=2x2−242x \cdot x - 4 \cdot 6 = 2x^2 - 24.

Setting equal: 2x2−24=−18⇒2x2=6⇒x2=3⇒x=±32x^2 - 24 = -18 \Rightarrow 2x^2 = 6 \Rightarrow x^2 = 3 \Rightarrow x = \pm\sqrt{3}.

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