x/(x^2+3)(x^2+4) dx = Option 1: 1/2(x^2+4/x^2+3) + C Option 2: (x^2+3/x^2+4) + C Option 3: 1/2(x^2+3/x^2+4) + C Option 4: (x^2+4/x^2+3) + C

The answer is '1/2(x^2+3/x^2+4) + C'. View full solution:

CUET Mathematics - x/(x^2+3)(x^2+4) dx = | PYQs + Solutions

CUET Mathematics 2022 4 Aug Shift 1

Calculus

Medium

$\frac{1}{2}\log\left(\frac{x^2+4}{x^2+3}\right) + C$

$\log\left(\frac{x^2+3}{x^2+4}\right) + C$

$\frac{1}{2}\log\left(\frac{x^2+3}{x^2+4}\right) + C$

$\log\left(\frac{x^2+4}{x^2+3}\right) + C$

✅ Correct Option: 3