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The system of equations in 3 variables x,yx, y and zz as x+y=5x+y=5, y+az=3y+az=3, x+by=8x+by=8 has a unique solution if the value of aa and bb are

(A) a=1,b=1a=1, b=1

(B) a=0,b=1a=0, b=1

(C) a∈(−∞,0)a \in (-\infty,0) and b≠1b\neq1

(D) a≠0a\neq0 and b∈(3,4)b\in(3,4)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

The coefficient determinant is ∣11001a1b0∣=a(1−b)\begin{vmatrix}1&1&0\\0&1&a\\1&b&0\end{vmatrix}=a(1-b). A unique solution requires a≠0a\neq0 and b≠1b\neq1. (A) and (B) both fail; (C) has a<0a<0 with b≠1b\neq1, and (D) has a≠0a\neq0 with b∈(3,4)b\in(3,4), so both work.

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