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The value of ∫−11∣x4−x∣ dx\displaystyle\int_{-1}^{1}|x^4-x|\,dx is equal to:

Solution

✅ Correct Option: 4

On [0,1][0,1], x4≤xx^4\le x, so the integrand is x−x4x-x^4 with integral 12−15=310\dfrac12-\dfrac15=\dfrac{3}{10}. On [−1,0][-1,0], x4−x≥0x^4-x\ge0, giving 15+12=710\dfrac15+\dfrac12=\dfrac{7}{10}. Adding, the value is 11.

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