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If AA is a 3×33\times 3 matrix with ∣A∣=4|A|=4, then ∣4A∣|4A| is equal to :

Solution

✅ Correct Option: 2

For a square matrix of order nn, ∣kA∣=kn∣A∣|kA|=k^n|A|. Here n=3n=3, so ∣4A∣=43×4=64×4=256|4A|=4^3\times4=64\times4=256.

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