The minimum value of f(x) = 4x^3 - 48x + 105 in the interval [1,3] is : Option 1: 61 Option 2: 41 Option 3: 32 Option 4: 69

The answer is '41'. View full solution:

CUET Mathematics - The minimum value of f(x) = 4x^3 - 48x + 105 in the interval [1,3] is : | PYQs + Solutions

CUET Mathematics 2023 7 June Shift 1

Applied Mathematics

Medium

✅ Correct Option: 2

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