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A die is rolled thrice. What is the probability of getting a number greater than 4 in the first and the second throw of dice and a number less than 4 in the third throw?

Solution

✅ Correct Option: 4

P(number>4)=P(5 or 6)=26=13P(\text{number} > 4) = P(5 \text{ or } 6) = \frac{2}{6} = \frac{1}{3}.

P(number<4)=P(1,2 or 3)=36=12P(\text{number} < 4) = P(1, 2 \text{ or } 3) = \frac{3}{6} = \frac{1}{2}.

Since throws are independent:

P=13×13×12=118P = \frac{1}{3} \times \frac{1}{3} \times \frac{1}{2} = \frac{1}{18}.

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