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Match List - I with list- II

List-I Equation of curvesList - II Slope of tangent at x = 2
A. Y=x3−xY = x^3 - x8
B. Y=(x−2)2Y = (x-2)^22/3
C. Y=2x2+3Y = 2x^2 + 311
D. Y=4x+1−7Y = \sqrt{4x + 1} - 70

Choose the correct option below :

Solution

✅ Correct Option: 3

Compute dydx\frac{dy}{dx} at x=2x = 2 for each curve.

A: y=x3−x⇒y′=3x2−1=11y = x^3 - x \Rightarrow y' = 3x^2 - 1 = 11 at x=2 (List II value 11 is at row III).

B: y=(x−2)2⇒y′=2(x−2)=0y = (x-2)^2 \Rightarrow y' = 2(x-2) = 0 at x=2 (value 0 at row IV).

C: y=2x2+3⇒y′=4x=8y = 2x^2 + 3 \Rightarrow y' = 4x = 8 at x=2 (value 8 at row I).

D: y=4x+1−7⇒y′=24x+1=23y = \sqrt{4x+1} - 7 \Rightarrow y' = \frac{2}{\sqrt{4x+1}} = \frac{2}{3} at x=2 (value 2/3 at row II).

Match: A-III, B-IV, C-I, D-II.

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